Question

gauge A has a pitch of 1 mm and 50 division on its circular scale gauge B has a pitch of 0.5 mm and 100 divisions on its circular scale. If (L × C) is least count, then which possibility is true ? What is the parilrility ?

(A) 2(L × C)A = (L × C)B

(B) (L × C)A = 4(L × C)B

(C) (L × C)A = (L × C)B

(D) (L × C)A = 2(L × C)B

Answer 1

The correct option is (B) (L × C)A = 4(L × C)B.

Explanation:

Least count = [{pitch} / {Number of division on circular scale}]

∴ (LC)A = {(1 mm) / (50 division)} = 0.02 mm/division

(LC)B = {(0.5 mm) / (100 division)} = 0.005 mm/division

∴ [{(L × C)A} / {(L × C)B}] = {(0.02) / (0.005)} = 4

∴ (L × C)A = 4(L × C)B