The correct option (a) 0
Explanation:
y = [(sin2x)/(1 – cotx)] + [(cos2x)/(1 – tanx)]
= [(sin2x)/(1 – {(cosx)/(sinx)})] + [(cos2x)/(1 – {(sinx)/(cosx)})]
= [(sin3x)/(sinx – cosx)] – [(cos3x)/(sinx – cosx)]
∴ y = sin2x + cos2x + sinxcosx
∴ y = 1 + [(sin2x)/2]
(dy/dx) = (1/2) × cos2x (2)
∴ (dy/dx) = cos2x
∴ |(dy/dx)|x=(π/4) = cos(π/2)
= 0