In Δ ABC and ΔDEF if m∠A = m∠D. m∠B = m∠E. AB = 2 cm, BC = 3 cm and DE = 6 cm, then what is EF in cm ?
(A) 9
(B) 7
(C) 5
(D) 3
The correct option is (A) 9
Explanation:
In ΔABC & ΔDEF
∠ A = ∠ D
∠ B = ∠ E
so by AA similarity
ΔABC ~ ΔDEF