Steps of Constructions :
Step 1 : Draw QR = 6 cm at Q draw an angle of P of 60°.
Step 2 : Draw ∠XPR = 60° from Q draw an arc of 5 cm. which is point P.therefore Δ PQR is the required triangle.
Step 3 : From Q draw an acute angle ∠ RQY.
Step 4 : From Q draw equal arc i.e., QQ1 = Q1Q2 = Q2Q3 = Q3Q4 = Q4Q5.
Step 5 : Join Q5 to R, draw line parallel to Q5R from Q2. Which intersect QR at R’ from R’. draw line
parallel to PR. which intersect PQ at P’
Step 6 : P’QR’ is the required triangle ΔABC.
