The correct option (D) 4 Ω
Explanation:
initially P.d = 10V with r = 1Ω
when R is connected p.d = 8V
∴ (V'/I) = r parallel with R
∴ (V'/I) = {(r ∙ R)/(r + R)} = {(1 × R)/(1 + R) = {R/(R + 1)}
Also initially V = Ir hence I = (V/r) = (10/1) = 10A
∴ (V'/I) = (8/10) = {R/(R + 1)}
∴ 8R + 8 = 10R
∴ R = 4Ω