Question

n identical cells each of e.m.f E and internal resistance r are connected in series An external resistance R is connected in series to this combination the current through R is.

(A) {(nE)/(R + nr)}

(B) {(nE)/(nR + r)}

(C) {E/(R + nr)}

(D) {(nE)/(R + r)}

Answer 1

The correct option (A) {(nE)/(R + nr)}

Explanation:

i = {(Total emf)/(Total resistance)}

= {nE/(R + nr)}.