+3 votes
in Mathematics by kratos

A flat circular ring has mass M, outer radius a and inner radius b (see figure). The measured values of these quantities are M = 0.191 ± 0.003 kg, a = 110 ± 1 mm and b = 15 ± 1 mm, the moment of inertia of the ring about an axis passing through the centre, and normal to the plane of the ring along with its error is: (Given I = M/2 (a2 + b2))

(A) (1.18 ± 0.04) × 10–3 kg m2

(B) (1.18 ± 0.02) × 10–3 kg m2

(C) (1.18 ± 0.05) × 10–3 kg m2

(D) (1.18 ± 0.08) × 10–3 kg m2

1 Answer

+4 votes
by kratos
 
Best answer

Correct option: (A) (1.18 ± 0.04) × 10–3 kg m2

Explanation:

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