The correct option (c) 1
Explanation:
∵ B = [{(μ0I)/(2πa2)} ∙ r]
for r = (a/2),
B = [(μ0I)/(2πa2)] × (a/2) = [(μ0I)/(4πa)] (inside the wire)
B' = [(μ0I)/(2πr)]
for r = 2a, B' = [(μ0I)/(2π × 2a)] = [(μ0I)/(4πa)] (outside the wire)
∴ B = B'
Hence the ratio is 1.