The correct option (d) √5(μ0/4π) (M/d3)
Explanation:
Let point P is midway between them due for magnet 1, induction at P is
B1 = (μ0/4π)(2M/d3) …………… (axis point)
due to magnet 2, induction at P is
B2 = (μ0/4π)(M/d3)…….. [Perpendicular point]
Bnet = √[(B12) + (B22)]
= √[{(μ0/4π)(2M/d3)}2 + {(μ0/4π)(M/d3)2}]
= (μ0/4π)(M/d3)√(4 + 1) = [{√(5)Mμ0}/(4πd3)]