40 mL of mixture of hydrogen and oxygen gases was placed in a gas burette at 48°C and 1 atm pressure. A spark was applied so that the formation of water is complete. The volume of the remaining hydrogen gas was 10 ml at 48°C and 1 atm pressure. Find the initial mole percentage of hydrogen in the mixture.
2H2(g) + O2(l) → 2H2O(l)
Total initial vol. of H2 and O2 = 40 ml.
At const pressure and temperature conditions.
volume of remaining H2= 10 ml.
H2 & O2 react in 2 : 1 molar ratio
there for volume of H2 reacted = 20 ml.
& vol. of O2 reacted = 10 ml.
