A straight line with slope 2 and y - intercept 5 touches the circle, x2 + y2 + 16x +12y + c =0 at a point Q. Then the coordinates of Q are
(A) (–6, 11)
(B) (–9, –13)
(C) (–10, –15)
(D) (–6, –7)
Correct option (D) (–6, –7)
Explanation:
Centre of circle is (– 8, –6)
Equation of line is y = 2x + 5
∴ Q is the foot of perpendicular of (– 8, –6) on 2x – y + 5 = 0