+3 votes
in JEE by kratos

A straight line with slope 2 and y - intercept 5 touches the circle, x2 + y2 + 16x +12y + c =0 at a point Q. Then the coordinates of Q are

(A) (–6, 11)

(B) (–9, –13)

(C) (–10, –15)

(D) (–6, –7)

1 Answer

+1 vote
by kratos
 
Best answer

Correct option (D) (–6, –7)

Explanation:

Centre of circle is (– 8, –6)

Equation of line is y = 2x + 5

∴ Q is the foot of perpendicular of (– 8, –6) on 2x – y + 5 = 0

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