Correct option: (3) 0.16(AA); 0.48(Aa); 0.36(aa)
Explanation:
Frequency of dominant allele (say p) = 0.4
Frequency of recessive allele (say q)
= 1 – 0.4 = 0.6
∴ Frequency of homozygous dominant individuals (AA)
= p2 = (0.4)2 = 0.16
Frequency of heterozygous individuals (Aa)
= 2pq = 2(0.4)(0.6) = 0.48
Frequency of homozygous recessive individuals (aa)
= q2 = (0.6)2 = 0.36