The heat capacity of one mole an ideal is found to be CV = 3R (1 + aRT)/2 where a is a constant.

Question 1

The heat capacity of one mole an ideal is found to be CV = 3R (1 + aRT)/2 where a is a constant. The equation obeyed by this gas during a reversible adiabatic expansion is -

(A) TV3/2 e aRT= constant

(B) TV3/2e3aRT/ 2= constant

(C) TV3 /2 = constant

(D) TV3/2 e2aRT/ 3 = constant

Question 2

Correct option (A) TV3/2 eaRt = constant

Explanation:

So no option is matching may be due to printing mistake

kratos · Answer 1 · 2020-11-14T20:05:57+0000

Correct option (A) TV3/2 eaRt = constant

Explanation:

So no option is matching may be due to printing mistake

The heat capacity of one mole an ideal is found to be CV = 3R (1 + aRT)/2 where a is a constant.

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1 Answer

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The heat capacity of one mole an ideal is found to be CV = 3R (1 + aRT)/2 where a is a constant.

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1 Answer

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