Find the length of the hypotenuse of a square whose side is 16 cm.
ABCD is a square.
In right angled triangle ∆ ABC,
AC2 = AB2 + BC2 ....(by Pythagoras theorem)
∴ AC2 = 162 + 162
∴ AC2 = 256 + 256
∴ AC2 = 512
∴ AC = 16 √2