An alternating voltage v(t) = 220 sin 100πt volt is applied to a purely resistive load of 50Ω. The time taken for the current

Question 1

An alternating voltage v(t) = 220 sin 100πt volt is applied to a purely resistive load of 50Ω. The time taken for the current to rise from half of the peak value to the peak value is -

(1) 5 ms (2) 7.2 ms (3) 3.3 ms (4) 2.2 ms

Question 2

Correct option (3) 3.3 ms

Explanation:

An alternating voltage v(t) = 220 sin 100πt volt is applied to a purely resistive load of 50Ω. The time taken for the current

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An alternating voltage v(t) = 220 sin 100πt volt is applied to a purely resistive load of 50Ω. The time taken for the current

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1 Answer

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