Question

the product of two numbers is 4107.if the hcf of these numbers is 37,then the greater number is?

Answer 1

Let the numbers be 37a and 37b.

Then, 37a x 37b = 4107

⇒ ab = 3.

Now, co-primes with product 3 are (1, 3).

So, the required numbers are (37 x 1, 37 x 3)

i.e., (37, 111).

∴ Greater number = 111.