+1 vote
in JEE by kratos

Two capacitors A and B are connected in series across a 100V supply and it is observed that the potential difference across them are 60V and 40V. A capacitor of 2µF capacitance is now connected in parallel with A and the potential difference across with A and the potential difference acorss B rise to 90V. Determine the capacitance of A and B.

1 Answer

+2 votes
by kratos
 
Best answer

We have CA x 60 =CB x 40 ( q charge is same)

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