An arrow is shot from a bow at an angle of 40 from the horizontal at a speed of 24.0 m/. Ignoring air resistance, what is the arrow’ maximum height above its launch point?
(A) 5.9 m
(B) 11.9 m
(C) 16.9 m
(D) 23.8 m
(E) 28.8 m
Correct option (B) 11.9 m
Maximum height of a projectile is found from vy = 0 at max height and vy2 = viy2 + 2gh and gives hmax = viy2/2g = (vi sinθ)2/2g
