Question

Acetyl bromide when reacts with excess of CH3MgI followed by treatment with saturated solution of NH4Cl it gives:

(1) Acetone

(2) Acetamide

(3) 2-methyl-2-propanol

(4) acetyl iodide

Answer 1

Acetyl bromide when reacts with excess of CH3MgI followed by treatment with saturated solution of NH4Cl it gives 2-methyl-2-propanol