Question

The equilibrium constant for a reaction is 1 × 1020 at 300 K. The standard Gibbs energy change for this reaction is:

(A) – 115 kJ (B) + 115 kJ (C) + 166 kJ (D) – 166 kJ

Answer 1

Correct option (A) – 115 kJ

Explanation:

∆G° = - 2.303 RT log Kp

=− 20 × 2.303 x 8.314 x 300 log 1020

= -114.88 kJ