Question

What volume of 10M HCl and 3M HCl should be mixed to obtain 1L of 6M HCl solution?

Answer 1

Let the required volume of 10M HCl be V liters

Then, the required volume of 3M HCl be (1 – V) Liters.

Then the volume of 10M HCl required = 428mL & volume of 3M HCl required = 1000mL – 428mL = 572mL