+1 vote
in JEE by kratos

A particle is projected from point A with speed u and angle of projection is o 60° . At some instant magnitude of velocity of particle is v and it makes an angle θ with horizontal. If radius of curvature of path of particle at the given instant is 8/3 √3 times of the minimum radius of curvature during the whole flight, then angle θ is

(A) θ = 37

(B) θ = 30

(C) θ = 45

(D) θ =15

1 Answer

+2 votes
by kratos
 
Best answer

Correct option (B) θ = 30

Explanation:

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