A parachutist after bailing out falls 50 m without friction. When parachute opens, it decelerates at 2m/*^2 .

Question

A parachutist after bailing out falls 50 m without friction. When parachute opens, it decelerates at 2m/s2. He reaches the ground with a speed of 3m/*. At what height, did he bail out?

(a) 293m

(b) 111m

(c) 91m

(d) 182m

Answer 1

(a) : Initially, the parachutist falls under gravity
Therefore, u 2 = 2ah = 2 × 9.8 × 50 = 980 m 2 –2
He reaches the ground with speed
= 3 m/, a = –2 ms –2

Therefore, (3) 2 = u 2 – 2 × 2 × h 1
or 9 = 980 – 4 h 1
or h1= 971/4

or h 1 = 242.75 m
Therefore, Total height = 50 + 242.75
= 292.75
= 293 m.u200b