+3 votes
in Class 12 by kratos

Let n be a natural number and let 'a' be a real number. The number of zeros of x2n+1 – (2n + 1) x + a = 0 in the interval [–1, 1] is –

(A) 2 if a > 0

(B) 2 if a < 0

(C) At most one for every value of a

(D) At least three for every value of a

1 Answer

+2 votes
by kratos
 
Best answer

Correct :- (C) At most one for every value of a

Explanation :-

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