Let n be a natural number and let 'a' be a real number. The number of zeros of x2n+1 – (2n + 1) x + a = 0 in the interval [–1, 1] is –
(A) 2 if a > 0
(B) 2 if a < 0
(C) At most one for every value of a
(D) At least three for every value of a
Correct :- (C) At most one for every value of a
Explanation :-