+2 votes
in Class 12 by kratos

A person standing near the edge of the top of a building throws two ***** A and B. The ball A is thrown vertically upward and B is thrown vertically downward with the same speed. The ball A hits the ground with a speed vA and the ball B hits the ground with a speed vB. We have

(a) vA > vB

(b) vA < vB

(c) vA = vB

(d) the relation between vA and vB depends on height of the building above the ground.

1 Answer

+1 vote
by kratos
 
Best answer

The correct answer is

(c) v**A = vB**

Explanation:

The ball 'A' thrown vertically upward will return back to the initial point with the same thrown speed but its direction will be downwards. This return speed is exactly the same as the speed of ball 'B'. So both of them will hit the ground with equal velocity.

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