+3 votes
in Mathematics by kratos

What change in volume would a 300-mm cube of steel suffer at a depth of 5 km in sea water? For steel E = 208 GPa, v = 0.3 and weight density of sea water, w = 1 × 10−5N/mm3.

1 Answer

+2 votes
by kratos
 
Best answer

Young’* modulus,

E = 208 × 103N/mm3

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