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Integrate : ∫3/2√xdx (A) √x^3 + C (B) √x + C

+3 votes

asked Feb 9, 2019 in JEE by kratos

Integrate : ∫3/2√xdx

(A) √x3 + C

(B) √x + C

(C) x + C

(D) 1/√x + C

indefinite integral
jee
methods of integration
indefinite integration
jee main
class-12

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1 Answer

+6 votes

answered Jun 17, 2020 by kratos

Best answer

Correct option (A) √x3 + C

Explanation:

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