+2 votes
in JEE by kratos

The system shown is in limiting equilibrium. The coefficient of friction for all contact surfaces is 1/4.

(A) tan = 3/8

(B) Tension in the string = (100/3 g sin θ)N

(C) Net frictional force on 80 kg block is (80 g sin θ )N

(D) Force exerted by 20 kg block on 80 kg block is (20 g cosθ)

1 Answer

+3 votes
by kratos
 
Best answer

Correct option (A) (B)(C)

Explanation:

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