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Find equation of circle with center (4,3) & touching 5x – 12y – 10 = 0
+3
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asked
Apr 1, 2019
in
JEE
by
kratos
Find equation of circle with center (4,3) & touching 5x – 12y – 10 = 0
circle
class-11
jee
circles
conic sections
jee mains
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1
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+4
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answered
Jan 21, 2020
by
kratos
Best answer
x2 + y2 – 8x – 6y + 21 = 0
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