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find equation of hyperbola referred to principal axes eccentricity = 5/3 & distance between directrices = 18/5

+2 votes

asked Mar 25, 2019 in JEE by kratos

find equation of hyperbola referred to principal axes eccentricity = 5/3 & distance between directrices = 18/5

hyperbola
jee
jee mains

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1 Answer

+3 votes

answered Apr 20, 2020 by kratos

Best answer

Eccentricity = 5/3 & distance between directrices = 18/5

Let the equation of the hyperbola be

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