Let x ∈ R and let
P = [(1,1,1),(0, 2, 2), (0, 0, 3)], Q = [(2, x, x),(0, 4, 0),(x, x ,6)] and R = PQP–1.
Then which of the following options is/are correct?
(B) For x = 1, there exists a unit vector
(D) There exists a real number x such that PQ = QP
Correct option: (A, C)
Explanation:
On both sides a12 elements are not equal for any value of x. So there exists no value of x for which PQ = QP.
