+2 votes
in JEE by kratos

In the system shown in figure at some instant acceleration of pully was 10 m/sec2 in upward direction. At that instant spring was in its natural length. If acceleration of block A and B are aA and aB at that instant then :

(Given mA = 10 kg , mB = 20 kg , g = 10 m/sec2 , pulley is light and smooth)

(A) aA = 10/3m/sec2 upward aB = 10/3 m/sec2 downward

(B) aA = aB = 5 m/sec2 upward

(C) aA = aB = 10 m/sec2 downward

(D) of these

1 Answer

+2 votes
by kratos
 
Best answer

Correct option (C) aA = aB = 10 m/sec2 downward

Explanation:

Tension in the string is zero. Blocks are in free fall state.

aA = aB = g↓

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