If f1 (x) = x, f2 (x) = 1 – x, f3 (x) = 1/x, f4(x) = 1/(1 - x), f5(x) = x/(x - 1), f6(X) = (x - 1)/x suppose that f6 (fm (x)) = f4 (x) and fn (f4 (x)) = f3 (x), then :
(A) m = 5
(B) n = 5
(C) m = 6
(D) n = 6
Correct option (B) (C)
Explanation:
