The rate of formation of NO(g) in the reaction NOBr(g)→ NO(g) + Br2 (g) is found to be 1.6 × 10^–4 M/*.

Question 1

The rate of formation of NO(g) in the reaction NOBr(g)→ NO(g) + Br2 (g) is found to be 1.6 × 10–4 M/*. Find the rate of overall reaction rate and rate of consumption of NOBr.

Question 2

We have :

First write a balanced chemical equation. 2NOBr(g)→ 2NO(g) + Br2 (g)

Now, Rate of overall reaction

kratos · Answer 1 · 2020-03-14T15:04:02+0000

We have :

First write a balanced chemical equation. 2NOBr(g)→ 2NO(g) + Br2 (g)

Now, Rate of overall reaction

The rate of formation of NO(g) in the reaction NOBr(g)→ NO(g) + Br2 (g) is found to be 1.6 × 10^–4 M/*.

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The rate of formation of NO(g) in the reaction NOBr(g)→ NO(g) + Br2 (g) is found to be 1.6 × 10^–4 M/*.

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