+3 votes
in JEE by kratos

A 3-digit number has, from left to right, the digits a, b and c with a > c. When the number with the digits reversed is subtracted from the original number, the unit’* digit in the difference is 4. The next two digits, from right to left, are

(A) 5 and 9

(B) 9 and 5

(C) 5 and 4

(D) 4 and 5

1 Answer

+3 votes
by kratos
 
Best answer

Correct option (B)

Explanation:

N = abc (let) ; a > c

New number N' = cba

Difference of digits at unit place = 4

⇒ 10 + c – a = 4

⇒ a – c = 6

then middle digit = 9 and first digit = a – 1 – c = 5

∴ then difference is 594

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