ABC is a triangular plate of uniform thickness. The sides are in the ratio shown in the figure. IAB, IBC and ICA are the moments

Question 1

ABC is a triangular plate of uniform thickness. The sides are in the ratio shown in the figure. IAB, IBC and ICA are the moments of inertia of the plate about AB, BC and CA axes respectively. Which one of the following relations is correct?

(a) IAB > IBC

(b) IBC > IAB

(c) IAB + IBC = ICA

(d) ICA is maximum

Question 2

Correct option: (b) IBC > IAB

Explanation:

The intersection of medians is the centre of mass of the triangle. Since distances of centre of mass from the sides are related

kratos · Answer 1 · 2020-10-18T21:41:26+0000

Correct option: (b) IBC > IAB

Explanation:

The intersection of medians is the centre of mass of the triangle. Since distances of centre of mass from the sides are related

ABC is a triangular plate of uniform thickness. The sides are in the ratio shown in the figure. IAB, IBC and ICA are the moments

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ABC is a triangular plate of uniform thickness. The sides are in the ratio shown in the figure. IAB, IBC and ICA are the moments

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1 Answer

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