Question

In a ΔABC, if |(1,a,b),(1,c,a), (1, b, c)| = 0, then sin2 A + sin2 B + sin2C =

(a) 9/4

(b) 4/9

(c) 1

(d) 3√3

Answer 1

Correct option (a) 9/4

Explanation:

Here, sum of squares of three members can be zero if and only if a = b = c