Question

A triangular block of mass M with angles 30°, 60° and 90° rest with its 30° – 90° side on a horizontal table. A cubical block of mass m rests on 60° – 30° side. The acceleration which M must have relative to the table to keep m stationary relative to the triangular block is (assuming frictionless contact)

(a) g

(b) g / 2

(c) g / √3

(d) g / √5

Answer 1

Correct option: (c) g / √3

Explanation:

Use result, a = gtan θ, a = gtan 30° = g / √3