1 Answer

+6 votes
by kratos
 
Best answer

e^y=y^x

=> y loge=xlogy

=> y =xlogy

=> dy/dx=x/y(dy/dx)+logy

=> dy/dx=(1/logy)(dy/dx)+logy

=> dy/dx-(1/logy)(dy/dx)=logy

=> dy/dx-(1/logy)(dy/dx)=logy

=> (dy/dx)(1-1/logy)=logy

=> (dy/dx)(logy-1)/logy=logy

=> (dy/dx)=(logy)^2/(logy-1)

proved

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