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The K.E. of one mole of an ideal gas is E = (3/2) RT. Then Cp will be

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in JEE by kratos

The K.E. of one mole of an ideal gas is E = (3/2) RT. Then Cp will be

(a) 0.5 R

(b) 0.1 R

(c) 1.5 R

(d) 2.5 R

1 Answer

+5 votes
by kratos
 
Best answer

Correct option: (d) 2.5 R

Explanation:

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