Equipotential surfaces are shown in figure. Then the electric field strength will be
(a) 100 Vm–1 along X-axis
(b) 100 Vm–1 along Y-axis
(c) 200 Vm–1 at an angle 120° with X-axis
(d) 50 Vm–1 at an angle 120° with X-axis
Correct option: (c) 200 Vm–1 at an angle 120° with X-axis
Explanation:
Direction of E be perpendicular to the equipotential surface i.e. at 120° with X- axis.