Question

The angle of elevation of the top of a building from the foot of the tower is 30° and the angle of elevation of the top of the tower from the foot of the building is 60°. If the tower is 50 m high find the height of the building.

Answer 1

Let building be AB & tower be CD.

Given

Height of the tower = 50 m

Hence, CD = 50 m

Angle of elevation of top of building from foot of tower = 30o

Hence,

∠ACB = 30o

Angle of elevation of top of tower from foot of building = 60o

Hence,∠DBC = 60o

We need find height of building i.e. AB

Since building & tower are perpendicular to ground

∠ABC = 90o & ∠DBC = 90o