In problem 20 the envelope of the central peak contains 9 fringes. How many fringes lie between the first and the second minima of the envelop?

Question 1

Question 2

We have

The first minimum in the diffraction term occurs at α = π or, sinθ = λ/a. The second minimum occurs at α = 2π or, sinθ = 2λ/a.

The interference maxima occur at sinθ

The interference maxima lying between the sinθ = λ/a and sinθ = 2λ/a are

So, four fringes lie between the first and the second minima of the envelope.

kratos · Answer 1 · 2020-12-22T13:38:09+0000

We have

The first minimum in the diffraction term occurs at α = π or, sinθ = λ/a. The second minimum occurs at α = 2π or, sinθ = 2λ/a.

The interference maxima occur at sinθ

The interference maxima lying between the sinθ = λ/a and sinθ = 2λ/a are

So, four fringes lie between the first and the second minima of the envelope.

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