If the pressure potential is +0.16 mega pascals (mPa) and the osmotic potential is –0.24 mega pascals, then the water potential would be
(a) + 0.4 mPa
(b) +0.08 mPa
(c) – 0.08 mPa
(d) + 0.16 mPa.
Correct option: (c) – 0.08 mPa
Explanation:
The water potential is the sum of the osmotic potential (usually negative) and the pressure potential (usually positive), so WP = –0.24 + 0.16 = –0.08 mPa.
