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lf solution of the equation 3cos^2 θ – 2√3 sinθ cosθ – 3 sin^2 θ = 0 are nπ + π/r and nπ+ π/* then | r – * | =

+3 votes
in JEE by kratos

lf solution of the equation 3cos2 θ – 2√3 sinθ cosθ – 3 sin2 θ = 0 are nπ + π/r and nπ+ π/ then | r – | =

(A) 3

(B) 9

(C) 7

(D) 1

1 Answer

+5 votes
by kratos
 
Best answer

Correct option (B) 9

Explanation:

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