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in Class 12 by kratos

Derive an expression Magnetic force on a current-carrying conductor and using Oersted’* experiment.

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by kratos
 
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Force on a moving charge in uniform magnetic and electric fields:

Derivation of magnetic force on a current carrying conductor

Consider a rod of a uniform cross-sectional area A and length l. We shall assume one kind of mobile carriers as in a conductor (here electrons). Let the number density of these mobile charge carriers in it be n. Then the total number of mobile charge carriers in it is nAl. For a steady current I in this conducting rod, we may assume that each mobile carrier has an average drift velocity vd . In the presence of an external magnetic field vector B, the force on these carriers is:

where q is the value of the charge on a carrier. Now nqvd is the current density j and |(nq vd)|A is the current I. Thus,

where vector l is a vector of magnitude l, the length of the rod, and with a direction identical to the current I.

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