AOB, COD are two unequal line segments bisecting at right angles, then the locus of the point P such that PA ⋅ PB = PC ⋅ PD is a

Question 1

(1) Circle

(2) Parabola

(3) Ellipse

(4) Rectangular hyperbola

Question 2

Correct option (4) Rectangular hyperbola

Explanation:

Taking O as the origin, AB, CD as the x and y-axes, the coordinates of A, B, C, D can be taken as (a, 0), (− a, 0), (0, c), (0, − c) For any point P(x, y),

is a rectangular hyperbola (a ≠ c)

kratos · Answer 1 · 2020-09-06T15:53:34+0000

Correct option (4) Rectangular hyperbola

Explanation:

Taking O as the origin, AB, CD as the x and y-axes, the coordinates of A, B, C, D can be taken as (a, 0), (− a, 0), (0, c), (0, − c) For any point P(x, y),

is a rectangular hyperbola (a ≠ c)

AOB, COD are two unequal line segments bisecting at right angles, then the locus of the point P such that PA ⋅ PB = PC ⋅ PD is a

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AOB, COD are two unequal line segments bisecting at right angles, then the locus of the point P such that PA ⋅ PB = PC ⋅ PD is a

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1 Answer

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