+1 vote
in Physics by kratos

At time t = 0, two point objects A and B respectively are at pole and centre of curvature of a fixed concave mirror of focal length f. The velocity vectors of A and B are always vector vA = ui and vB = -ui respectively, where 'i' is unit vector along principal axis directed from pole towards focus and u is a positive constant.

The distance between images of A and B will be 4f at time t =

(A) f/√2u

(B) √2f/u

(C) f/2u

(D) f/4u

1 Answer

+1 vote
by kratos
 
Best answer

Correct option (C) f/2u

Explanation:

The image distance of A is vA

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