+2 votes
in Class 12 by kratos

The moment of inertia of a thin ring of mass M and radius R about its diameter is

(A) 1/2MR2

(B) 3/2(MR)2

(C) MR2

(D) 2MR2

1 Answer

+2 votes
by kratos
 
Best answer

Correct option (A)

Explanation:

using perpendicular axis theorem

I = 1/2MR2

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