+3 votes
in JEE by kratos

A symmetrical uniform solid cube of side 5 m is placed on a horizontal surface beside a vertical wall, one side of cube is making an angle 45° with the floor as shown. If coefficient of friction μ is the same for both wall and floor, the minimum value of μ for cube not to slip?

(A) μ = 1

(B) μ= 0

(C) μ= 1/3

(D) impossible to balance for any value of .

1 Answer

+2 votes
by kratos
 
Best answer

Correct option: (B) μ = 0

Explanation:

At angles 45 N and Mg balance each other and they both pass through COM, so no need of friction to balance it

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